What is Cube Root of 64

Answer: The Cube Root of 64 is 4

  • Cube root of 64 is written as 643\sqrt[3]{64} (Radical form).
  • 643\sqrt[3]{64} = 4×4×43\sqrt[3]{4 \times 4 \times 4} = 4
  • In the exponential form, the cube root of 64 is expressed as (64)13(64)^\frac{1}{3}.

Prime Factorization Method

  • Step 1: Prime factors of 64: 2 x 2 x 2 x 2 x 2 x 2
  • Step 2: Prime factors of 64 in triplets: (2 x 2 x 2) x (2 x 2 x 2)
  • Step 3: Now cube root of 64:

643=(2×2×2)×(2×2×2)3\sqrt[3]{64} = \sqrt[3]{(2 \times 2 \times 2) \times (2 \times 2 \times 2)}

643=23×233\sqrt[3]{64} = \sqrt[3]{ 2^3 \times2^3}

643=(2×2)3\sqrt[3]{64} = \sqrt{(2\times2)^3}

643=43\sqrt[3]{64} = \sqrt{4^3}

643=4\sqrt[3]{64} = 4

Therefore, the cube root of 64 is 4

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