What is Cube Root of 25

Answer: The Cube Root of 25 is 2.9240

  • Cube root of 25 is written as 253\sqrt[3]{25} (Radical form).
  • 253\sqrt[3]{25} = 2.9240×2.9240×2.92403\sqrt[3]{2.9240 \times 2.9240 \times 2.9240} = 2.9240
  • In the exponential form, the cube root of 25 is expressed as (25)13(25)^\frac{1}{3}.

Cube Root by Halley's Method

Halley's method is an iterative technique used to find cube roots. To find the cube root of a number using Halley's method, follow these steps:

Its formula is a3x((x3+2×a)(2×x3+a))\sqrt[3]{a} ≈ x \left( \frac{ \left( x^3 + 2 \times a \right) }{ \left( 2 \times x^3 + a \right) } \right) where,

• a = number whose cube root is being calculated = 25
• x = integer guess of its cube root.

Let's assume x as 2. Since 25 lies between 8 (cube of 2) and 27 (cube of 3). So, we will consider the closest cube number here, i.e. 3.

Using the above formula & numbers, let's calculate the cube root of 25

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