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Multiples of 1998 | Multiples - Definition, Calculations, Examples

Methods for Finding Multiples of 1998?

To find the first 10 multiples of 1998, multiply 1998 by each number from 1 to 10 in sequence:

$1998\times1 = 1998$

$1998\times2 = 3996$

$1998\times3 = 5994$

$1998\times4 = 7992$

$1998\times5 = 9990$

$1998\times6 = 11988$

$1998\times7= 13986$

$1998\times8 = 15984$

$1998\times9 = 17982$

$1998\times10 = 19980$

So, the first 10 multiples of 1998 are: 1998, 3996, 5994, 7992, 9990, 11988, 13986, 15984, 17982 and 19980.

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What are the Multiples of 1998? | The answer is 1998, 3996, 5994, 7992, 9990, 11988... Discover multiples, with definitions, examples, and easy-to-follow explanations and more at AskMathGuru.

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What are the Multiples of 1998?

Answer: Multiples of 1998 are 1998, 3996, 5994, 7992, 9990, 11988, 13986, 15984, 17982 and 19980

Methods for Finding Multiples of 1998?

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