What are the Multiples of 1992?

Answer: Multiples of 1992 are 1992, 3984, 5976, 7968, 9960, 11952, 13944, 15936, 17928 and 19920

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Methods for Finding Multiples of 1992?

To find the first 10 multiples of 1992, multiply 1992 by each number from 1 to 10 in sequence:

1992×1=19921992\times1 = 1992

1992×2=39841992\times2 = 3984

1992×3=59761992\times3 = 5976

1992×4=79681992\times4 = 7968

1992×5=99601992\times5 = 9960

1992×6=119521992\times6 = 11952

1992×7=139441992\times7= 13944

1992×8=159361992\times8 = 15936

1992×9=179281992\times9 = 17928

1992×10=199201992\times10 = 19920

So, the first 10 multiples of 1992 are: 1992, 3984, 5976, 7968, 9960, 11952, 13944, 15936, 17928 and 19920.

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Summary

What are the Multiples of 1992? | The answer is 1992, 3984, 5976, 7968, 9960, 11952... Discover multiples, with definitions, examples, and easy-to-follow explanations and more at AskMathGuru.

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