What are the Multiples of 1989?

Answer: Multiples of 1989 are 1989, 3978, 5967, 7956, 9945, 11934, 13923, 15912, 17901 and 19890

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Methods for Finding Multiples of 1989?

To find the first 10 multiples of 1989, multiply 1989 by each number from 1 to 10 in sequence:

1989×1=19891989\times1 = 1989

1989×2=39781989\times2 = 3978

1989×3=59671989\times3 = 5967

1989×4=79561989\times4 = 7956

1989×5=99451989\times5 = 9945

1989×6=119341989\times6 = 11934

1989×7=139231989\times7= 13923

1989×8=159121989\times8 = 15912

1989×9=179011989\times9 = 17901

1989×10=198901989\times10 = 19890

So, the first 10 multiples of 1989 are: 1989, 3978, 5967, 7956, 9945, 11934, 13923, 15912, 17901 and 19890.

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Summary

What are the Multiples of 1989? | The answer is 1989, 3978, 5967, 7956, 9945, 11934... Discover multiples, with definitions, examples, and easy-to-follow explanations and more at AskMathGuru.

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