What are the Multiples of 1988?

Answer: Multiples of 1988 are 1988, 3976, 5964, 7952, 9940, 11928, 13916, 15904, 17892 and 19880

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Methods for Finding Multiples of 1988?

To find the first 10 multiples of 1988, multiply 1988 by each number from 1 to 10 in sequence:

1988×1=19881988\times1 = 1988

1988×2=39761988\times2 = 3976

1988×3=59641988\times3 = 5964

1988×4=79521988\times4 = 7952

1988×5=99401988\times5 = 9940

1988×6=119281988\times6 = 11928

1988×7=139161988\times7= 13916

1988×8=159041988\times8 = 15904

1988×9=178921988\times9 = 17892

1988×10=198801988\times10 = 19880

So, the first 10 multiples of 1988 are: 1988, 3976, 5964, 7952, 9940, 11928, 13916, 15904, 17892 and 19880.

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Summary

What are the Multiples of 1988? | The answer is 1988, 3976, 5964, 7952, 9940, 11928... Discover multiples, with definitions, examples, and easy-to-follow explanations and more at AskMathGuru.

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