What is 99/93 Divided By 3/2

Answer: 9993÷32\frac{99}{93}\div\frac{3}{2} = 2231\frac{22}{31}

Solving 9993÷32\frac{99}{93}\div\frac{3}{2}

  • Rewrite the Division as Multiplication by the Reciprocal:

9993÷32=9993×23\frac{99}{93} \div \frac{3}{2} = \frac{99}{93} \times \frac{2}{3}

  • Multiply the Numerators: 99×2=19899 \times 2 = 198
  • Multiply the Denominators: 93×3=27993 \times 3 = 279
  • Form the New Fraction: 9993×32=198279\frac{99}{93} \times \frac{3}{2} = \frac{198}{279}

Let's Simplify 198279\frac{198}{279}

  • Find the Greatest Common Divisor (GCD) of 198198 and 279279. The GCD of 198198 and 279279 is 99.
  • Divide both the numerator and the denominator by the GCD:198÷9279÷9=2231\frac{198 \div 9}{279 \div 9} = \frac{22}{31}

Answer 9993÷32=2231\frac{99}{93}\div\frac{3}{2} = \frac{22}{31}


The following animation demonstrates the divide-by,

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