What is 98/99 Divided By 2/9

Answer: 9899÷29\frac{98}{99}\div\frac{2}{9} = 4911\frac{49}{11}

Solving 9899÷29\frac{98}{99}\div\frac{2}{9}

  • Rewrite the Division as Multiplication by the Reciprocal:

9899÷29=9899×92\frac{98}{99} \div \frac{2}{9} = \frac{98}{99} \times \frac{9}{2}

  • Multiply the Numerators: 98×9=88298 \times 9 = 882
  • Multiply the Denominators: 99×2=19899 \times 2 = 198
  • Form the New Fraction: 9899×29=882198\frac{98}{99} \times \frac{2}{9} = \frac{882}{198}

Let's Simplify 882198\frac{882}{198}

  • Find the Greatest Common Divisor (GCD) of 882882 and 198198. The GCD of 882882 and 198198 is 1818.
  • Divide both the numerator and the denominator by the GCD:882÷18198÷18=4911\frac{882 \div 18}{198 \div 18} = \frac{49}{11}

Answer 9899÷29=4911\frac{98}{99}\div\frac{2}{9} = \frac{49}{11}


The following animation demonstrates the divide-by,

©AskMathGuru
Need support for a different topic or want to share a feedback? Write to us and we'll work on adding it. Be a part of our progress!