What is 98/99 Divided By 2/3

Answer: 9899÷23\frac{98}{99}\div\frac{2}{3} = 4933\frac{49}{33}

Solving 9899÷23\frac{98}{99}\div\frac{2}{3}

  • Rewrite the Division as Multiplication by the Reciprocal:

9899÷23=9899×32\frac{98}{99} \div \frac{2}{3} = \frac{98}{99} \times \frac{3}{2}

  • Multiply the Numerators: 98×3=29498 \times 3 = 294
  • Multiply the Denominators: 99×2=19899 \times 2 = 198
  • Form the New Fraction: 9899×23=294198\frac{98}{99} \times \frac{2}{3} = \frac{294}{198}

Let's Simplify 294198\frac{294}{198}

  • Find the Greatest Common Divisor (GCD) of 294294 and 198198. The GCD of 294294 and 198198 is 66.
  • Divide both the numerator and the denominator by the GCD:294÷6198÷6=4933\frac{294 \div 6}{198 \div 6} = \frac{49}{33}

Answer 9899÷23=4933\frac{98}{99}\div\frac{2}{3} = \frac{49}{33}


The following animation demonstrates the divide-by,

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