What is 98/53 Divided By 4/9

Answer: 9853÷49\frac{98}{53}\div\frac{4}{9} = 441106\frac{441}{106}

Solving 9853÷49\frac{98}{53}\div\frac{4}{9}

  • Rewrite the Division as Multiplication by the Reciprocal:

9853÷49=9853×94\frac{98}{53} \div \frac{4}{9} = \frac{98}{53} \times \frac{9}{4}

  • Multiply the Numerators: 98×9=88298 \times 9 = 882
  • Multiply the Denominators: 53×4=21253 \times 4 = 212
  • Form the New Fraction: 9853×49=882212\frac{98}{53} \times \frac{4}{9} = \frac{882}{212}

Let's Simplify 882212\frac{882}{212}

  • Find the Greatest Common Divisor (GCD) of 882882 and 212212. The GCD of 882882 and 212212 is 22.
  • Divide both the numerator and the denominator by the GCD:882÷2212÷2=441106\frac{882 \div 2}{212 \div 2} = \frac{441}{106}

Answer 9853÷49=441106\frac{98}{53}\div\frac{4}{9} = \frac{441}{106}


The following animation demonstrates the divide-by,

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