What is 98/53 Divided By 4/5

Answer: 9853÷45\frac{98}{53}\div\frac{4}{5} = 245106\frac{245}{106}

Solving 9853÷45\frac{98}{53}\div\frac{4}{5}

  • Rewrite the Division as Multiplication by the Reciprocal:

9853÷45=9853×54\frac{98}{53} \div \frac{4}{5} = \frac{98}{53} \times \frac{5}{4}

  • Multiply the Numerators: 98×5=49098 \times 5 = 490
  • Multiply the Denominators: 53×4=21253 \times 4 = 212
  • Form the New Fraction: 9853×45=490212\frac{98}{53} \times \frac{4}{5} = \frac{490}{212}

Let's Simplify 490212\frac{490}{212}

  • Find the Greatest Common Divisor (GCD) of 490490 and 212212. The GCD of 490490 and 212212 is 22.
  • Divide both the numerator and the denominator by the GCD:490÷2212÷2=245106\frac{490 \div 2}{212 \div 2} = \frac{245}{106}

Answer 9853÷45=245106\frac{98}{53}\div\frac{4}{5} = \frac{245}{106}


The following animation demonstrates the divide-by,

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