What is 98/53 Divided By 4/1

Answer: 9853÷41\frac{98}{53}\div\frac{4}{1} = 49106\frac{49}{106}

Solving 9853÷41\frac{98}{53}\div\frac{4}{1}

  • Rewrite the Division as Multiplication by the Reciprocal:

9853÷41=9853×14\frac{98}{53} \div \frac{4}{1} = \frac{98}{53} \times \frac{1}{4}

  • Multiply the Numerators: 98×1=9898 \times 1 = 98
  • Multiply the Denominators: 53×4=21253 \times 4 = 212
  • Form the New Fraction: 9853×41=98212\frac{98}{53} \times \frac{4}{1} = \frac{98}{212}

Let's Simplify 98212\frac{98}{212}

  • Find the Greatest Common Divisor (GCD) of 9898 and 212212. The GCD of 9898 and 212212 is 22.
  • Divide both the numerator and the denominator by the GCD:98÷2212÷2=49106\frac{98 \div 2}{212 \div 2} = \frac{49}{106}

Answer 9853÷41=49106\frac{98}{53}\div\frac{4}{1} = \frac{49}{106}


The following animation demonstrates the divide-by,

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