What is 98/48 Divided By 5/9

Solving $\frac{98}{48}\div\frac{5}{9}$

• Rewrite the Division as Multiplication by the Reciprocal:

$\frac{98}{48} \div \frac{5}{9} = \frac{98}{48} \times \frac{9}{5}$

• Multiply the Numerators: $98 \times 9 = 882$
• Multiply the Denominators: $48 \times 5 = 240$
• Form the New Fraction: $\frac{98}{48} \times \frac{5}{9} = \frac{882}{240}$

Let's Simplify $\frac{882}{240}$

• Find the Greatest Common Divisor (GCD) of $882$ and $240$. The GCD of $882$ and $240$ is $6$.
• Divide both the numerator and the denominator by the GCD:$\frac{882 \div 6}{240 \div 6} = \frac{147}{40}$

Answer $\frac{98}{48}\div\frac{5}{9} = \frac{147}{40}$

The following animation demonstrates the divide-by,