What is 98/42 Divided By 1/5

Answer: 9842÷15\frac{98}{42}\div\frac{1}{5} = 353\frac{35}{3}

Solving 9842÷15\frac{98}{42}\div\frac{1}{5}

  • Rewrite the Division as Multiplication by the Reciprocal:

9842÷15=9842×51\frac{98}{42} \div \frac{1}{5} = \frac{98}{42} \times \frac{5}{1}

  • Multiply the Numerators: 98×5=49098 \times 5 = 490
  • Multiply the Denominators: 42×1=4242 \times 1 = 42
  • Form the New Fraction: 9842×15=49042\frac{98}{42} \times \frac{1}{5} = \frac{490}{42}

Let's Simplify 49042\frac{490}{42}

  • Find the Greatest Common Divisor (GCD) of 490490 and 4242. The GCD of 490490 and 4242 is 1414.
  • Divide both the numerator and the denominator by the GCD:490÷1442÷14=353\frac{490 \div 14}{42 \div 14} = \frac{35}{3}

Answer 9842÷15=353\frac{98}{42}\div\frac{1}{5} = \frac{35}{3}


The following animation demonstrates the divide-by,

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