What is 98/35 Divided By 3/2

Answer: 9835÷32\frac{98}{35}\div\frac{3}{2} = 2815\frac{28}{15}

Solving 9835÷32\frac{98}{35}\div\frac{3}{2}

  • Rewrite the Division as Multiplication by the Reciprocal:

9835÷32=9835×23\frac{98}{35} \div \frac{3}{2} = \frac{98}{35} \times \frac{2}{3}

  • Multiply the Numerators: 98×2=19698 \times 2 = 196
  • Multiply the Denominators: 35×3=10535 \times 3 = 105
  • Form the New Fraction: 9835×32=196105\frac{98}{35} \times \frac{3}{2} = \frac{196}{105}

Let's Simplify 196105\frac{196}{105}

  • Find the Greatest Common Divisor (GCD) of 196196 and 105105. The GCD of 196196 and 105105 is 77.
  • Divide both the numerator and the denominator by the GCD:196÷7105÷7=2815\frac{196 \div 7}{105 \div 7} = \frac{28}{15}

Answer 9835÷32=2815\frac{98}{35}\div\frac{3}{2} = \frac{28}{15}


The following animation demonstrates the divide-by,

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