What is 98/12 Divided By 9/3

Answer: 9812÷93\frac{98}{12}\div\frac{9}{3} = 4918\frac{49}{18}

Solving 9812÷93\frac{98}{12}\div\frac{9}{3}

  • Rewrite the Division as Multiplication by the Reciprocal:

9812÷93=9812×39\frac{98}{12} \div \frac{9}{3} = \frac{98}{12} \times \frac{3}{9}

  • Multiply the Numerators: 98×3=29498 \times 3 = 294
  • Multiply the Denominators: 12×9=10812 \times 9 = 108
  • Form the New Fraction: 9812×93=294108\frac{98}{12} \times \frac{9}{3} = \frac{294}{108}

Let's Simplify 294108\frac{294}{108}

  • Find the Greatest Common Divisor (GCD) of 294294 and 108108. The GCD of 294294 and 108108 is 66.
  • Divide both the numerator and the denominator by the GCD:294÷6108÷6=4918\frac{294 \div 6}{108 \div 6} = \frac{49}{18}

Answer 9812÷93=4918\frac{98}{12}\div\frac{9}{3} = \frac{49}{18}


The following animation demonstrates the divide-by,

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