What is 81/48 Divided By 9/5

Solving $\frac{81}{48}\div\frac{9}{5}$

• Rewrite the Division as Multiplication by the Reciprocal:

$\frac{81}{48} \div \frac{9}{5} = \frac{81}{48} \times \frac{5}{9}$

• Multiply the Numerators: $81 \times 5 = 405$
• Multiply the Denominators: $48 \times 9 = 432$
• Form the New Fraction: $\frac{81}{48} \times \frac{9}{5} = \frac{405}{432}$

Let's Simplify $\frac{405}{432}$

• Find the Greatest Common Divisor (GCD) of $405$ and $432$. The GCD of $405$ and $432$ is $27$.
• Divide both the numerator and the denominator by the GCD:$\frac{405 \div 27}{432 \div 27} = \frac{15}{16}$

Answer $\frac{81}{48}\div\frac{9}{5} = \frac{15}{16}$

The following animation demonstrates the divide-by,