What is 81/12 Divided By 9/5

Answer: 8112÷95\frac{81}{12}\div\frac{9}{5} = 154\frac{15}{4}

Solving 8112÷95\frac{81}{12}\div\frac{9}{5}

  • Rewrite the Division as Multiplication by the Reciprocal:

8112÷95=8112×59\frac{81}{12} \div \frac{9}{5} = \frac{81}{12} \times \frac{5}{9}

  • Multiply the Numerators: 81×5=40581 \times 5 = 405
  • Multiply the Denominators: 12×9=10812 \times 9 = 108
  • Form the New Fraction: 8112×95=405108\frac{81}{12} \times \frac{9}{5} = \frac{405}{108}

Let's Simplify 405108\frac{405}{108}

  • Find the Greatest Common Divisor (GCD) of 405405 and 108108. The GCD of 405405 and 108108 is 2727.
  • Divide both the numerator and the denominator by the GCD:405÷27108÷27=154\frac{405 \div 27}{108 \div 27} = \frac{15}{4}

Answer 8112÷95=154\frac{81}{12}\div\frac{9}{5} = \frac{15}{4}


The following animation demonstrates the divide-by,

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