What is 48/99 Divided By 2/9

Answer: 4899÷29\frac{48}{99}\div\frac{2}{9} = 2411\frac{24}{11}

Solving 4899÷29\frac{48}{99}\div\frac{2}{9}

  • Rewrite the Division as Multiplication by the Reciprocal:

4899÷29=4899×92\frac{48}{99} \div \frac{2}{9} = \frac{48}{99} \times \frac{9}{2}

  • Multiply the Numerators: 48×9=43248 \times 9 = 432
  • Multiply the Denominators: 99×2=19899 \times 2 = 198
  • Form the New Fraction: 4899×29=432198\frac{48}{99} \times \frac{2}{9} = \frac{432}{198}

Let's Simplify 432198\frac{432}{198}

  • Find the Greatest Common Divisor (GCD) of 432432 and 198198. The GCD of 432432 and 198198 is 1818.
  • Divide both the numerator and the denominator by the GCD:432÷18198÷18=2411\frac{432 \div 18}{198 \div 18} = \frac{24}{11}

Answer 4899÷29=2411\frac{48}{99}\div\frac{2}{9} = \frac{24}{11}


The following animation demonstrates the divide-by,

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