What is 48/81 Divided By 9/5

Solving $\frac{48}{81}\div\frac{9}{5}$

• Rewrite the Division as Multiplication by the Reciprocal:

$\frac{48}{81} \div \frac{9}{5} = \frac{48}{81} \times \frac{5}{9}$

• Multiply the Numerators: $48 \times 5 = 240$
• Multiply the Denominators: $81 \times 9 = 729$
• Form the New Fraction: $\frac{48}{81} \times \frac{9}{5} = \frac{240}{729}$

Let's Simplify $\frac{240}{729}$

• Find the Greatest Common Divisor (GCD) of $240$ and $729$. The GCD of $240$ and $729$ is $3$.
• Divide both the numerator and the denominator by the GCD:$\frac{240 \div 3}{729 \div 3} = \frac{80}{243}$

Answer $\frac{48}{81}\div\frac{9}{5} = \frac{80}{243}$

The following animation demonstrates the divide-by,