What is 39/27 Divided By 1/5

Answer: 3927÷15\frac{39}{27}\div\frac{1}{5} = 659\frac{65}{9}

Solving 3927÷15\frac{39}{27}\div\frac{1}{5}

  • Rewrite the Division as Multiplication by the Reciprocal:

3927÷15=3927×51\frac{39}{27} \div \frac{1}{5} = \frac{39}{27} \times \frac{5}{1}

  • Multiply the Numerators: 39×5=19539 \times 5 = 195
  • Multiply the Denominators: 27×1=2727 \times 1 = 27
  • Form the New Fraction: 3927×15=19527\frac{39}{27} \times \frac{1}{5} = \frac{195}{27}

Let's Simplify 19527\frac{195}{27}

  • Find the Greatest Common Divisor (GCD) of 195195 and 2727. The GCD of 195195 and 2727 is 33.
  • Divide both the numerator and the denominator by the GCD:195÷327÷3=659\frac{195 \div 3}{27 \div 3} = \frac{65}{9}

Answer 3927÷15=659\frac{39}{27}\div\frac{1}{5} = \frac{65}{9}


The following animation demonstrates the divide-by,

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