What is 35/28 Divided By 9/3

Answer: 3528÷93\frac{35}{28}\div\frac{9}{3} = 512\frac{5}{12}

Solving 3528÷93\frac{35}{28}\div\frac{9}{3}

  • Rewrite the Division as Multiplication by the Reciprocal:

3528÷93=3528×39\frac{35}{28} \div \frac{9}{3} = \frac{35}{28} \times \frac{3}{9}

  • Multiply the Numerators: 35×3=10535 \times 3 = 105
  • Multiply the Denominators: 28×9=25228 \times 9 = 252
  • Form the New Fraction: 3528×93=105252\frac{35}{28} \times \frac{9}{3} = \frac{105}{252}

Let's Simplify 105252\frac{105}{252}

  • Find the Greatest Common Divisor (GCD) of 105105 and 252252. The GCD of 105105 and 252252 is 2121.
  • Divide both the numerator and the denominator by the GCD:105÷21252÷21=512\frac{105 \div 21}{252 \div 21} = \frac{5}{12}

Answer 3528÷93=512\frac{35}{28}\div\frac{9}{3} = \frac{5}{12}


The following animation demonstrates the divide-by,

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