What is 28/35 Divided By 3/9

Answer: 2835÷39\frac{28}{35}\div\frac{3}{9} = 125\frac{12}{5}

Solving 2835÷39\frac{28}{35}\div\frac{3}{9}

  • Rewrite the Division as Multiplication by the Reciprocal:

2835÷39=2835×93\frac{28}{35} \div \frac{3}{9} = \frac{28}{35} \times \frac{9}{3}

  • Multiply the Numerators: 28×9=25228 \times 9 = 252
  • Multiply the Denominators: 35×3=10535 \times 3 = 105
  • Form the New Fraction: 2835×39=252105\frac{28}{35} \times \frac{3}{9} = \frac{252}{105}

Let's Simplify 252105\frac{252}{105}

  • Find the Greatest Common Divisor (GCD) of 252252 and 105105. The GCD of 252252 and 105105 is 2121.
  • Divide both the numerator and the denominator by the GCD:252÷21105÷21=125\frac{252 \div 21}{105 \div 21} = \frac{12}{5}

Answer 2835÷39=125\frac{28}{35}\div\frac{3}{9} = \frac{12}{5}


The following animation demonstrates the divide-by,

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