What is 22/99 Divided By 3/9

Answer: 2299÷39\frac{22}{99}\div\frac{3}{9} = 23\frac{2}{3}

Solving 2299÷39\frac{22}{99}\div\frac{3}{9}

  • Rewrite the Division as Multiplication by the Reciprocal:

2299÷39=2299×93\frac{22}{99} \div \frac{3}{9} = \frac{22}{99} \times \frac{9}{3}

  • Multiply the Numerators: 22×9=19822 \times 9 = 198
  • Multiply the Denominators: 99×3=29799 \times 3 = 297
  • Form the New Fraction: 2299×39=198297\frac{22}{99} \times \frac{3}{9} = \frac{198}{297}

Let's Simplify 198297\frac{198}{297}

  • Find the Greatest Common Divisor (GCD) of 198198 and 297297. The GCD of 198198 and 297297 is 9999.
  • Divide both the numerator and the denominator by the GCD:198÷99297÷99=23\frac{198 \div 99}{297 \div 99} = \frac{2}{3}

Answer 2299÷39=23\frac{22}{99}\div\frac{3}{9} = \frac{2}{3}


The following animation demonstrates the divide-by,

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