What is 22/98 Divided By 3/9

Answer: 2298÷39\frac{22}{98}\div\frac{3}{9} = 3349\frac{33}{49}

Solving 2298÷39\frac{22}{98}\div\frac{3}{9}

  • Rewrite the Division as Multiplication by the Reciprocal:

2298÷39=2298×93\frac{22}{98} \div \frac{3}{9} = \frac{22}{98} \times \frac{9}{3}

  • Multiply the Numerators: 22×9=19822 \times 9 = 198
  • Multiply the Denominators: 98×3=29498 \times 3 = 294
  • Form the New Fraction: 2298×39=198294\frac{22}{98} \times \frac{3}{9} = \frac{198}{294}

Let's Simplify 198294\frac{198}{294}

  • Find the Greatest Common Divisor (GCD) of 198198 and 294294. The GCD of 198198 and 294294 is 66.
  • Divide both the numerator and the denominator by the GCD:198÷6294÷6=3349\frac{198 \div 6}{294 \div 6} = \frac{33}{49}

Answer 2298÷39=3349\frac{22}{98}\div\frac{3}{9} = \frac{33}{49}


The following animation demonstrates the divide-by,

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