What is 22/33 Divided By 3/9

Answer: 2233÷39\frac{22}{33}\div\frac{3}{9} = 21\frac{2}{1}

Solving 2233÷39\frac{22}{33}\div\frac{3}{9}

  • Rewrite the Division as Multiplication by the Reciprocal:

2233÷39=2233×93\frac{22}{33} \div \frac{3}{9} = \frac{22}{33} \times \frac{9}{3}

  • Multiply the Numerators: 22×9=19822 \times 9 = 198
  • Multiply the Denominators: 33×3=9933 \times 3 = 99
  • Form the New Fraction: 2233×39=19899\frac{22}{33} \times \frac{3}{9} = \frac{198}{99}

Let's Simplify 19899\frac{198}{99}

  • Find the Greatest Common Divisor (GCD) of 198198 and 9999. The GCD of 198198 and 9999 is 9999.
  • Divide both the numerator and the denominator by the GCD:198÷9999÷99=21\frac{198 \div 99}{99 \div 99} = \frac{2}{1}

Answer 2233÷39=21\frac{22}{33}\div\frac{3}{9} = \frac{2}{1}


The following animation demonstrates the divide-by,

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