What is Cube Root of 7

Answer: The Cube Root of 7 is 1.9129

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  • Cube root of 7 is written as 73\sqrt[3]{7} (Radical form).
  • 73\sqrt[3]{7} = 1.9129×1.9129×1.91293\sqrt[3]{1.9129 \times 1.9129 \times 1.9129} = 1.9129
  • In the exponential form, the cube root of 7 is expressed as (7)13(7)^\frac{1}{3}.

Cube Root by Halley's Method

Halley's method is an iterative technique used to find cube roots. To find the cube root of a number using Halley's method, follow these steps:

Its formula is a3x((x3+2×a)(2×x3+a))\sqrt[3]{a} ≈ x \left( \frac{ \left( x^3 + 2 \times a \right) }{ \left( 2 \times x^3 + a \right) } \right) where,

• a = number whose cube root is being calculated = 7
• x = integer guess of its cube root.

Let's assume x as 1. Since 7 lies between 1 (cube of 1) and 8 (cube of 2). So, we will consider the closest cube number here, i.e. 2.

Using the above formula & numbers, let's calculate the cube root of 7

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